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I think, i'm good with derivatives like this. can ...
Solution to Problem 2
Solution to Problem 1
Some practice derivatives, per Nadav's request
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Daniel
Ian
Nadav
ajo
Wednesday, November 28, 2007
Solution to Problem 1
We will use the chain rule and product rule.
By the chain rule
.
Now we must use the chain rule again.
. Now apply the product and sum rules to the last part.
=
=
.
Putting this all together gives the answer
.
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